Vishant Bhatia(0798567), Tulaib Bin
Ayyub(0789141), Alisha Mahajan(0802631)
We,Vishant Bhatia, Tulaib Bin Ayyub, and Alisha Mahajan hereby state
that we have not communicated with or gained information in any way from
any person or resource that would violate the College’s academic
integrity policies, and that all work presented is our own. In addition,
we also agree not to share our work in any way, before or after
submission, that would violate the College’s academic integrity
policies.
R version used- R version 4.2.1 (2022-06-23 ucrt)
RStudio used- 2022.07.1 version
List of R packages used- tidyverse, here, plotly, ggplot2.
Library Imported and their versions
tidyverse : 1.3.2
here : 1.0.1
plotly : 4.10.0
ggplot2 : 3.3.6
Contribution of each member:
Prepared one Histogram plot displaying distribution about a
single numerical variable i.e Age of Winning Candidates.
Prepared one Box plot displaying information about outliers
of above numerical variable.
Prepared one Bar chart displaying count information about
one categorical variable i.e Category of winning candidates.
Prepared one Pie chart displaying proportions information
about above categorical variable.
Prepared one Scatter Plot displaying information about pair
of Numerical variable Age and General Votes.
Prepared one Scatter Plot displaying information about pair
of one Numerical variable Age and one categorical variable
Category.
Tulaib Bin Ayyub(0789141)
Prepared one Histogram plot displaying distribution about a
single numerical variable i.e Postal Votes.
Prepared one Box plot displaying information about outliers
of above numerical variable.
Prepared one Bar chart displaying count information about
one categorical variable i.e State.
Prepared one Pie chart displaying proportions information
about above categorical variable.
Prepared one Scatter Plot displaying information about pair
of Numerical variable Age and Postal Votes.
Prepared one Scatter Plot displaying information about pair
of one Numerical variable Age and one categorical variable
Winner
Prepared one Histogram plot displaying distribution about a
single numerical variable i.e General Votes.
Prepared one Box plot displaying information about outliers
of above numerical variable.
Prepared one Bar chart displaying count information about
one categorical variable i.e Education of candidates.
Prepared one Pie chart displaying proportions information
about above categorical variable.
Prepared one Scatter Plot displaying information about pair
of Numerical variable Age and Total Votes.
Prepared one Scatter Plot displaying information about pair
of one Numerical variable Age and one categorical variable
State
Dataset: Indian Election 2019
https://www.kaggle.com/code/paramarthasengupta/eda-plotly-prediction-indian-elections-2019
Datatypes and Variables
STATE—-chr type
CONSTITUENCY—-chr type
NAME—-chr type
WINNER—-int type
PARTY—-chr type
SYMBOL—-chr type
GENDER—-chr type
CRIMINAL.CASES—-chr type
AGE—-int type
CATEGORY—-chr type
EDUCATION—-chr type
ASETS—-chr type
LIABILITIES—-chr type
GENERAL.VOTES—-int type
POSTAL.VOTES—-int type
TOTAL.VOTES—-int type
OVER.TOTAL.ELECTORS.IN.CONSTITUENCY→ num type
OVER.TOTAL.VOTES.POLLED..IN.CONSTITUENCY→ num type
TOTAL.ELECTORS—-int type
library("tidyverse")
library("here")
library("plotly")
library("ggplot2")
library("plotrix")
setwd("C:\\F Drive\\BAsic stats DAB 501\\Project 2")
indian_election_df <- read.csv("Indian_Election_2019.csv")
#indian_election_df
1. Create an appropriate plot to visualize the distribution of this
variable.
indian_election_df_winner <- indian_election_df %>%
filter(WINNER == 1)
# here we are filtering out data only of winning candidates of Indian Election 2019
ggplotly(indian_election_df_winner %>%
ggplot(aes(x = AGE)) +
geom_histogram(binwidth = 3,color = "yellow",fill = "red")+
labs(title="Distribution of Ages for Winning Candidate",
y = "Count", x = "Age of Winning Candidate") )
NA
In Above Histogram plot we can say that there are many winning
candidates in Indian Election 2019 most of the ages are lies between
45-69.
2. Consider any outliers present in the data. If present, specify
the criteria used to identify them and provide a logical explanation for
how you handled them.
ggplotly(indian_election_df_winner %>%
ggplot(aes(y = AGE)) +
geom_boxplot(color = "Red", fill = "cyan")+
labs(title="Distribution of Ages for Winning Candidate",
x = "Count", y = "Age of Winning Candidate"))
NA
NA
NA
In Above box plot we can clearly see that Median of winning
candidates of Indian Election 2019 is 55, and most of the data lies
between 47-63 age.
There are many ways to find Outliers in above boxplot but the
accurate way is:
First we have to find the distance between First Quartile (Q1)
and Third Quartile (Q3), which is called Interquartile (IQR)
Anything which is beyond Q3 + 1.5 times the IQR and anything
which is less than Q1 - 1.5 times the IQR gives the possible
outliers.These are those observations which are away from box.
3.Most Probable outliers are those values that are more than or less
than above statement.
For Example in our above BoxPlot:- Q1 = 47 Q3 = 63 IQR = Q3-Q1 =
16
possible outliers are values > = Q3 + 1.5 * IQR called capping and
values < = Q1 - 1.5 * IQR calling flooring
Values > = 87 (capping) values < = 23 (flooring)
According to this formula and after studying above histogram plot we
can say that we have one outlier that is 87 and it’s count is 1.
There are many ways to handle outliers.
First is we can remove that record.But it is not recommended.
Second way is if there are so many outliers values we can assign the
value nearer to that outlier. for example if values are greater than 99
percentile then we can assign the 99th percentile value, and if value is
less than 1 percentile then we can assign the 1st percentile value to
that outlier.
Third way is assign that value which is nearer to the median and
outlier.
3. Describe the shape and skewness of the distribution
Ans–> In our 1st question we make histogram plot. The shape of
Histogram is somehow symmetry and bell shaped.
5. Choose and calculate an appropriate measure of central
tendency.
Ans–> The word “central tendancy” is fairly common in statistics.
It’s a technique to explain how your data are distributed. While central
tendancy does not provide you with the fine details of your data, it
does provide you with a general notion of how your data are
distributed.
The mean, median, and mode are the three most widely used parameters
of central tendency. The median of an ordered dataset is the value in
the centre, whereas the mean or average is equal to the sum of all the
values in the data set divided by the number of values in the data set.
On the other side, mode shows you the dataset’s most repeatable value.
So in our case we are using mean as central tendency.
mean(indian_election_df_winner$AGE)
[1] 54.44156
6. Explain why you chose this as your measure of central tendency.
Provide supporting evidence for your choice.
Because age is an issue and we need to know the average age of the
candidates who would win the 2019 Indian Election, we have chosen “Mean”
as the central tendency. The victorious candidates’ average age is now
54.44. Since the mean and median values in this situation are about
equal, we can also compute the median here. We are using visualisation
to demonstrate this proof (Box plot and Histogram).
ggplotly(indian_election_df_winner %>%
ggplot(aes(y = AGE)) +
geom_boxplot(color = "Red", fill = "cyan")+
labs(title="Distribution of Ages for Winning Candidate",
x = "Count", y = "Age of Winning Candidate"))
NA
In above boxplot it is clearly shown that median of age is 55.
ggplotly(indian_election_df_winner %>%
ggplot(aes(x = AGE)) +
geom_histogram(binwidth = 3,color = "yellow",fill = "red")+
labs(title="Distribution of Ages for Winning Candidate",
y = "Count", x = "Age of Winning Candidate") )
NA
In above Histogram we can say that mean is just near about 54.50.
7. Choose and calculate a measure of spread that is appropriate for
your chosen measure of central tendency. Explain why you chose this as
your measure of spread.
We have following factors for measure of spread or measure of
dispersion 1. Range 2. Inter-Quartile Range 3. Variance 4. Mean
Deviation 5. Standard Deviation
sd(indian_election_df_winner$AGE)
[1] 11.04964
In above question we use Standard Deviation because When data is
distributed relatively normally, the standard deviation performs
exceptionally well and provides information similar to that of the IQR.
But the IQR is typically favored for data that is obviously
non-normal.But in our case Age is just normally distributed.
Categorical Variable : CATEGORY
For each categorical variable :
1. Create an appropriate plot to visualize the distribution of
counts for this variable.
ggplotly(indian_election_df_winner %>%
ggplot(aes(x = CATEGORY)) +
geom_bar(color = "black",fill = "cyan")+
labs(title="Count of Different Categories of Winning Candidate",
y = "Count", x = "Category") )
NA
NA
2. Create an appropriate plot to visualize the distribution of
proportions for this variable.
pie_data <- table(indian_election_df_winner$CATEGORY)
lbls <- paste(names(pie_data), "\n", pie_data, sep="")
pie3D(pie_data, labels = lbls,
main = "Proportions of Different Categories of Winning Candidate")

NA
NA
NA
3. Discuss any unusual observations for this variable?
Ans–> There is only one unusual observation in above categorical
variable. Out of 539, 55 are from ST category or we can say that aprox
only 10 % of candidates are from ST category which is like an outlier of
our data.
4. Discuss if there are too few/too many unique values?
Ans-> There are only 3 unique values in our categorical variable
i.e General Category, SC Category and ST Category.
unique(indian_election_df_winner$CATEGORY)
[1] "ST" "SC" "GENERAL"
One pair of Numeric Variable : AGE and General Votes
One pair of Numeric and Categorical Variable : AGE and
Category
1. Create an appropriate plot to visualize the relationship between
the two variables.
- For 1st Pair
indian_election_df_winner <- indian_election_df_winner %>% mutate(GENERAL.VOTES=GENERAL.VOTES/10000)
ggplotly(indian_election_df_winner_sort %>%
ggplot(aes(x = AGE, y = GENERAL.VOTES)) +
geom_point() +
geom_smooth(formula = y ~ x, method = "lm") +
labs(title="Comaprison of Age and General Votes",
y = "No. of General Votes", x = " Age"))
NA
- For 2nd Pair
ggplotly(indian_election_df_winner %>%
ggplot(aes(x = CATEGORY, y = AGE, fill = CATEGORY)) +
geom_point()+
labs(title="Comaprison of Category and Age of Winning Candidates ",
y = "Age", x = "Category"))
NA
NA
3. Explain what this relationship means in the context of the
data?
Ans–> The significance of the correlation coefficient for the
variables indicates the direction of the relationship between the two.
Positive relationships are denoted with a “plus” symbol, whereas bad
relationships are denoted by a “minus” sign.
Positive –> When two variables are positively correlated, they
both tend to move in the same direction: If one grows, the other usually
follows suit. One tends to diminish when the other does as well.
Negative –> When two variables are negatively correlated, they
often move in the opposite directions: if one grows, the other tends to
drop, and vice versa.
The form is refered to the whether relationship is linear or non
linear.
Linear–>A straight connection is referred to as being linear since
it resembles a straight line.
Curvilinear–> Because a curved connection resembles a curved line,
it is referred to as being curvilinear.
We exclusively work with correlation coefficients that measure linear
relationships in this Value. Other correlation coefficients exist that
quantify curved relationships, but they are advanced in nature.
Perfect Relationship–>The coefficient of correlation is either
+1.00 or -1.00 when two variables are linearly connected. Either
favourably or negatively, it is claimed that they are precisely linearly
connected.
No Relationship–>Relationship: When there is absolutely no
connection between two variables, their correlation coefficient is
0.00.
For all these things we use coefficient of correlation. Predictions
may be made with the use of correlations. We may expect that two
variables will continue to correlate in the ahead if they have been
shown to do so in the past. To forecast the value that the other
variable will have in the future, we may utilise the value of one
variable.
4. Describe the variability that you observe in the plot and how
that corresponds to the strength you calculated in no. 2 above.
Variance–> The statistical assessment of the variation in numbers
within a data collection is known as variance. In more detail, variance
assesses how far apart each number in the collection is from the mean
(average) and, consequently, from each other. The square root of the
variance is the Standard Deviation.
We can learn more about our data than what is often shown by
conventional statistical summaries by using a scatterplot to visualise
it. Bivariate data can be summarised using one of two fundamental
methods: regression analysis or correlation analysis. Regression
analysis describes how to leverage the relationship between the two
components to forecast or control one variable using the other. The
standard error of estimate and coefficient of determination, both equal
to the square of the correlation r, are two indicators of how well a
regression analysis performed. The former indicates the typical size of
prediction errors, while the latter indicates the proportion of the Y
variable’s variability that is “explained” by the X variable.
Now, in our first scatter plot, we can observe that the majority of
the data is present for both the variable x and y axis in the middle of
the graph.
According to strength of our data our scatter plot is weak in
relationship. I must say it is negative in relationship.
Tulaib Bin Ayyub (0789141)
Numeric Variable : Postal Votes
df_ind_elec <- read.csv("Indian_Election_2019.csv")
df_ind_elec
#Univariate #Numeric variable:
Ques1. Create an appropriate plot to visualize the distribution of
this variable.
ggplotly(df_ind_elec %>%
ggplot(aes(POSTAL.VOTES))+
geom_histogram(binwidth = 70, color = "darkblue")+
labs(title = "DISTRIBUTION OF POSTAL VOTES", x = "Number Of Postal Votes", y = "Count"))
NA
Ques2. Consider any outliers present in the data. If present,
specify the criteria used to identify them and provide a logical
explanation for how you handled them.
ggplotly(df_ind_elec %>%
ggplot(aes(y = POSTAL.VOTES))+
geom_boxplot(fill = "skyblue"))
Ans2. After looking at the generated boxplot, we can clearly see that
there are multiple outliers. To handle the outliers we can impute them
with median if they are close to median or we can impute them with any
value closer to the outliers which is not an outlier.
Ques3. Describe the shape and skewness of the distribution.
mean(df_ind_elec$POSTAL.VOTES)
[1] 990.7106
Ans3. After finding the mean above and median in question 2, we can
say that the shape and skewness of the distribution are unimodel and
right skewed because most of the data are in left part.
Ques5. Choose and calculate an appropriate measure of central
tendency.
mean(df_ind_elec$POSTAL.VOTES)
[1] 990.7106
Ques6. Explain why you chose this as your measure of central
tendency. Provide supporting evidence for your choice.
ggplotly(df_ind_elec %>% ggplot(aes(y = POSTAL.VOTES))+
geom_boxplot(fill = "skyblue"))
Ans6. Chose this because it is showing the average of postal votes
which is very different in comparison to the median. In this boxplot we
can see the median is low i.e., 316.00 and the mean was 990.7106 as we
saw in previous answer.
Ques7. Choose and calculate a measure of spread that is appropriate
for your chosen measure of central tendency. Explain why you chose this
as your measure of spread.
sd(df_ind_elec$POSTAL.VOTES)
[1] 1602.839
Ans. To calculate measures of spread we can use minimum value,
maximum value, standard deviation, variance, interquartile(IQR), etc. We
are taking standard deviation and the value is high so the value in the
data set are spread over a wide range.
Categorical Variable : State
Categorical variable:
Ques1. Create an appropriate plot to visualize the distribution of
counts for this variable.
ggplotly(df_ind_elec %>% ggplot(aes(STATE))+
geom_bar(fill = "skyblue", color = "black")+
coord_flip()+
labs(title = "DISTRIBUTION OF STATES", x = "States", y = "Count"))
Ques2. Create an appropriate plot to visualize the distribution of
proportions for this variable.
df_ind_elec %>%
ggplot(aes(x = factor(1), fill = factor(STATE)))+
geom_bar(width = 1)+
coord_polar(theta = 'y', start = 0)+
labs(title = "PROPORTIONS OF DIFFERENT STATES", x = "States")

NA
NA
Ques3. Discuss any unusual observations for this variable?
Ans3. Having too many value in this variable which is making it hard
to interpret the visualization.
Ques4. Discuss if there are too few/too many unique values?
unique(df_ind_elec$STATE)
[1] "Telangana" "Uttar Pradesh"
[3] "Maharashtra" "Gujarat"
[5] "Rajasthan" "Kerala"
[7] "West Bengal" "Uttarakhand"
[9] "Andhra Pradesh" "Haryana"
[11] "Punjab" "Jammu & Kashmir"
[13] "Andaman & Nicobar Islands" "Tamil Nadu"
[15] "Bihar" "Arunachal Pradesh"
[17] "Odisha" "Assam"
[19] "Karnataka" "Madhya Pradesh"
[21] "Chhattisgarh" "Chandigarh"
[23] "NCT OF Delhi" "Jharkhand"
[25] "Dadra & Nagar Haveli" "Daman & Diu"
[27] "Himachal Pradesh" "Manipur"
[29] "Lakshadweep" "Mizoram"
[31] "Nagaland" "Goa"
[33] "Puducherry" "Meghalaya"
[35] "Sikkim" "Tripura"
Ans4. Yes there are too many unique values i.e., 36.
One pair of Numeric Variable : AGE and Postal Votes
One pair of Numeric and Categorical Variable : AGE and
Winner
Ques1. Create an appropriate plot to visualize the relationship
between the two variables.
Ans1. 1. Plot using two numerical variables.
df_ind_elec <- df_ind_elec %>%
mutate(POSTAL.VOTES = POSTAL.VOTES/100)
ggplotly(df_ind_elec %>%
ggplot(aes(x = AGE, y = POSTAL.VOTES))+
geom_point(color = "skyblue")+
geom_smooth(method = "gam",
formula = y ~ s(x, bs = "cs")))
Warning: Removed 245 rows containing non-finite values (stat_smooth).
- Plot using one numerical and one categorical variable.
ggplotly(df_ind_elec %>%
ggplot(aes(x = WINNER, y = AGE))+
geom_point(color = "skyblue"))
Ques3. Explain what this relationship means in the context of the
data.
Ans3. This relationship means to understand and find the correlation
between two variables. So that we can find the positive, negative,
curvilinear relationship. We can say the relationship is perfect if the
value lies between -1 to +1 and a no relationship when no relation is
found so the correlation is 0. To find the relationship we use
correlation coefficient.
Ques4. Describe the variability that you observe in the plot and how
that corresponds to the strength
you calculated in #2 above.
Ans4. By utilizing a scatter plot to visualize our data, we may
discover more about it than what is frequently shown by traditional
statistical summaries. One of the two primary techniques—correlation
analysis or regression analysis—can be used to summarize bivariate data.
Regression analysis explains how to take advantage of the connection
between the two elements to predict or regulate one parameter using the
other. Two measures of how well a regression analysis worked are the
standard error of estimate and coefficient of determination, both equal
to the square of the correlation r. Indicated by the latter is the
percentage of the Y variable’s variability that can be “explained” by
the X variable, the former indicating the average size of prediction
mistakes. Scatter plot shows a rather good and fairly strong
relationship with the quality of our data and it is a possibly positive
relationship
Numeric Variable : GENERAL VOTES
ind_elec <- read.csv("Indian_election_2019.csv")
1. Create an appropriate plot to visualize the distribution of this
variable.
ind_elec <- ind_elec %>%
mutate(GENERAL.VOTES = GENERAL.VOTES/1000)
ggplot(ind_elec, aes(x = GENERAL.VOTES))+
geom_histogram( color = "BLUE", fill = "YELLOW") +
labs(title="Distribution of general votes in 2019 election",
y = "Count", x = "No. of general votes")

In the above histogram, it can be seen that there is right skewed
distribution where general votes lies mostly on left side.
2.Consider any outliers present in the data. If present, specify the
criteria used to identify them and provide a logical explanation for how
you handled them.
ggplotly(ind_elec %>%
ggplot(aes(y = GENERAL.VOTES)) +
geom_boxplot(color = "Red", fill = "blue")+
labs(title="Distribution of General votes in 2019 election",
x = "Count", y = "General Votes"))
In above box plot, it can be seen that there are many outliers in
this plot which can be calculated as:
Interquartile (IQR) = Q3-Q1 = 485.81 - 21.03 = 464.78
possible outliers: values > = Q3 + 1.5 * IQR (capping) and values
< = Q1 - 1.5 * IQR (flooring)
values > = 1182.98 and values < = -676.14
So, according to this formula, there is no outliers in this plot. but
in my analysis there are some outliers which falls between 485.81 and
1066.82.
How to handel outliers:
- first way to handle these outliers is to simply delete it or remove
it. But this is not an appropriate way.
- second way is to assign that value which is nearer value.
- And Third way is to find the mean, if it is nearby the values then
we take that value.
3. Describe the shape and skewness of the distribution?
Ans: The shape of the distribution is unimodel as it has one hump and
it can be clearly seen that there is right skewed distribution where
general votes lies mostly on left side.
5 . Choose and calculate an appropriate measure of central
tendency.
Ans: Central tendency: The statistical measure that designates one
value as being representative of a whole distribution is known as
central tendency. [2] The complete set of data will be accurately
described. It is the single value that best characterizes or
encapsulates the information gathered.
Mean, median and mode are three ways that are used to measure central
tendency.
median_value <- median(ind_elec$GENERAL.VOTES)
median_value
[1] 153.934
mean_value <- mean(ind_elec$GENERAL.VOTES)
mean_value
[1] 261.5991
6. Explain why you chose this as your measure of central tendency.
Provide supporting evidence for your choice .
Ans: After analyzing central tendency for mean and median of variable
general votes, I take mean as the measure for central tendency because
it it more accurate than median and also our data is mostly on left side
and also we are calculated average of general votes. so, mean is best
suited for this variable.
7. Choose and calculate a measure of spread that is appropriate for
your chosen measure of central tendency. Explain why you chose this as
your measure of spread.
Ans: We can calculate measure of spread in many ways like Range, IQR,
Variance, Mean deviation, Standard deviation. but here I am calculating
variance for general votes:
var(ind_elec$GENERAL.VOTES)
[1] 65020.2
The average squared deviation from the mean, also known as variance,
gives us the average dispersion from the mean for a given set of data.
However, if an outlier is present, the value returned after squaring the
deviation from the mean would be excessively large, which immediately
leads us to the conclusion that an outlier is present in the data set.
When you calculate the variance, you’ll see that the result is
abnormally high in the big picture. We basically take the square root of
these numbers to restore them to their normal value and give us a number
that is much more typical in order to account for this.
Categorical Variable : EDUCATION
1.Create an appropriate plot to visualize the distribution of counts
for this variable.
ggplotly(ind_elec %>%
ggplot(aes(x = EDUCATION)) +
geom_bar(color = "bLUE",fill = "PINK")+
labs(title="Count of Education Candidate",
y = "Count", x = "Education") )
2. Create an appropriate plot to visualize the distribution of
proportions for this variable.
ind_elec %>%
ggplot(aes(x = factor(1), fill = factor(EDUCATION)))+
geom_bar( width = 1)+
coord_polar(theta = 'y', start = 0)+
labs(title="Proportions of Education of Candidate",
y = "Count", x = "Education")

NA
NA
NA
3. Discuss any unusual observations for this variable.
Ans: There are some unusual observations of Eductaion categorical
variable like
- In some observations there are duplicate values.
- In some of the cases there are missing values.
- In this variable some values are “Not Available”
4. Discuss if there are too few/too many unique values?
Ans:There are total 13 unique values, we have in this categorical
variable.
unique(ind_elec$EDUCATION)
[1] "12th Pass" "Post Graduate" ""
[4] "Doctorate" "Graduate" "Others"
[7] "10th Pass" "8th Pass" "Graduate Professional"
[10] "Literate" "Illiterate" "5th Pass"
[13] "Not Available" "Post Graduate\n"
One pair of Numeric Variable : AGE and Total Votes
One pair of Numeric and Categorical Variable : AGE and
STATE
1. Create an appropriate plot to visualize the relationship between
the two variables.
ind_elc <- ind_elec %>%
mutate(TOTAL.VOTES=TOTAL.VOTES/1000)
ggplotly(ind_elc%>%
ggplot(aes(x = AGE, y = TOTAL.VOTES, color = CATEGORY)) +
geom_point() +
geom_smooth(formula = y ~ x, method = "lm") +
labs(title="Comparison of Age and Total Votes",
y = "No. of Total Votes", x = " Age"))
Warning: Removed 245 rows containing non-finite values (stat_smooth).
- For 2nd pair
ggplotly(ind_elc %>%
ggplot(aes(x = AGE, y = STATE, fill = STATE)) +
geom_point()+
labs(title="Comparison of State and Age of Candidates ",
y = "State", x = "Age"))
NA
NA
3 Explain what this relationship means in the context of the
data.
Ans–> Understanding and determining the correlation between two
variables is what this connection refers to. in order to identify the
curvilinear, positive, and negative relationships. If the value is
between -1 and +1, then the relationship is perfect; otherwise, there is
no association, and the correlation is 0. We utilize the correlation
coefficient to discover the relationship. In our case correlation
coefficient is positive i.e + 0.208
4 Describe the variability that you observe in the plot and how that
corresponds to the strength
you calculated in #2 above.
Ans–> The Variance is the numerical measure of how thew data is
spread across the mean. The R language’s var() function calculates a
vector’s sample variance. It serves as a gauge for how much a value
deviates from the mean. The square root of the variance is the standard
deviation.
Two measures of how well a regression analysis worked are the
standard error of estimate and coefficient of determination, both equal
to the square of the correlation r. Indicated by the latter is the
percentage of the Y variable’s variability that can be “explained” by
the X variable, the former indicating the average size of prediction
mistakes.
Now in our first Scatter plot most of the data is present in the
bottom of the graph, which means mostly values of total votes are
less.
According to strength of our data our scatter plot is fairly strong
in relationship. I must say it is positive relation.
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<head>
<title> </title>
<body> <h4><b> <FONT COLOR="SKYBLUE">Vishant Bhatia(0798567), Tulaib Bin Ayyub(0789141), Alisha Mahajan(0802631)</FONT COLOR></b></h4>

<p> <b>We,Vishant Bhatia, Tulaib Bin Ayyub, and Alisha Mahajan hereby state that we have not communicated with or gained information in any way from any person or resource that would violate the College’s academic integrity policies, and that all work presented is our own. In addition, we also agree not to share our work in any way, before or after submission, that would violate the College’s academic integrity policies.</b></p>

<p>R version used- R version 4.2.1 (2022-06-23 ucrt)     </p>
<p>RStudio used- 2022.07.1 version      </p>

List of R packages used- tidyverse, here, plotly, ggplot2.

<h5> <b> Library Imported and their versions</b></h5>

<li>tidyverse : 1.3.2 </li>
<li>here : 1.0.1 </li>
<li>plotly : 4.10.0 </li>
<li>ggplot2 : 3.3.6</li>

<FONT SIZE=14><FONT COLOR="SKYBLUE"><b><h3> Contribution of each member:</h3></b></FONT COLOR></FONT SIZE>

<P><h4><ul><b>Vishant Bhatia(0798567)</b></ul><li><FONT SIZE=3>Prepared one Histogram plot displaying distribution about a single numerical variable i.e Age of Winning Candidates.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Box plot displaying information about outliers of above numerical variable.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Bar chart displaying count information about one categorical variable i.e Category of winning candidates.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Pie chart displaying proportions information about above categorical variable.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Scatter Plot displaying  information about pair of Numerical variable Age and General Votes.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Scatter Plot displaying information about pair of one Numerical variable Age and one categorical variable Category.</FONT SIZE></li><br>


<P><h4><ul><b>Tulaib Bin Ayyub(0789141)</b></ul><li><li><FONT SIZE=3>Prepared one Histogram plot displaying distribution about a single numerical variable i.e Postal Votes.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Box plot displaying information about outliers of above numerical variable.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Bar chart displaying count information about one categorical variable i.e State.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Pie chart displaying proportions information about above categorical variable.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Scatter Plot displaying  information about pair of Numerical variable Age and Postal Votes.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Scatter Plot displaying information about pair of one Numerical variable Age and one categorical variable Winner</FONT SIZE></li><br>


<P><h4><ul><b>Alisha Mahajan(0802631)</b></ul><li><FONT SIZE=3>Prepared one Histogram plot displaying distribution about a single numerical variable i.e General Votes.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Box plot displaying information about outliers of above numerical variable.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Bar chart displaying count information about one categorical variable i.e Education of candidates.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Pie chart displaying proportions information about above categorical variable.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Scatter Plot displaying  information about pair of Numerical variable Age and Total Votes.</FONT SIZE></li><li><FONT SIZE=3>Prepared one Scatter Plot displaying information about pair of one Numerical variable Age and one categorical variable State</FONT SIZE></li><br>

<h2><FONT COLOR="SKYBLUE"> Dataset: Indian Election 2019</FONT COLOR></h2>
<h4><p><ul> Source: </ul> <a href=https://www.kaggle.com/code/paramarthasengupta/eda-plotly-prediction-indian-elections-2019> https://www.kaggle.com/code/paramarthasengupta/eda-plotly-prediction-indian-elections-2019</a><br>
<br>
<h5> <b> Datatypes and Variables </b></h5>
<li> 
STATE----chr type
</li>
<li>  
CONSTITUENCY----chr type
</li>
<li>
NAME----chr type
</li>
<li>
WINNER----int type
</li>
<li>
PARTY----chr type
</li>
<li>
SYMBOL----chr type
</li>
<li>
GENDER----chr type
</li>
<li>
CRIMINAL.CASES----chr type
</li>
<li>
AGE----int type
</li>
<li>
CATEGORY----chr type
</li>
<li>
EDUCATION----chr type
</li>
<li>
ASETS----chr type
</li>
<li>
LIABILITIES----chr type
</li>
<li>
GENERAL.VOTES----int type
</li>
<li>
POSTAL.VOTES----int type
</li>
<li>
TOTAL.VOTES----int type
</li>
<li>
OVER.TOTAL.ELECTORS.IN.CONSTITUENCY→ num type
</li>
<li>
OVER.TOTAL.VOTES.POLLED..IN.CONSTITUENCY→ num type
</li>
<li>
TOTAL.ELECTORS----int type
</li>

<p>   </p>
<br>

<h4>


```{r}
library("tidyverse")
library("here")
library("plotly")
library("ggplot2")
library("plotrix")
```


```{r}
setwd("C:\\F Drive\\BAsic stats DAB 501\\Project 2")
```


<P><h3><ul><b>Vishant Bhatia(0798567)</b></ul><br>
<P><h5><ul><u>Univariate Analysis</u></ul><br>

<P><h5><ul>Numeric Variable : <b>AGE</b></ul><br>



```{r}
indian_election_df <- read.csv("Indian_Election_2019.csv") 

#indian_election_df

```


# 1. Create an appropriate plot to visualize the distribution of this variable.

```{r}
indian_election_df_winner <- indian_election_df %>% 
                                filter(WINNER == 1)

# here we are filtering out data only of winning candidates of Indian Election 2019
```


```{r}

ggplotly(indian_election_df_winner %>% 
  ggplot(aes(x = AGE)) +
  geom_histogram(binwidth = 3,color = "yellow",fill = "red")+
  labs(title="Distribution of Ages for Winning Candidate", 
       y = "Count", x = "Age of Winning Candidate") )

```

In Above Histogram plot we can say that there are many winning candidates in Indian Election 2019 most of the ages are lies between 45-69.



# 2. Consider any outliers present in the data. If present, specify the criteria used to identify them and provide a logical explanation for how you handled them.


```{r}
ggplotly(indian_election_df_winner %>% 
  ggplot(aes(y = AGE)) +
  geom_boxplot(color = "Red", fill = "cyan")+
  labs(title="Distribution of Ages for Winning Candidate", 
       x = "Count", y = "Age of Winning Candidate"))



```

In Above box plot we can clearly see that Median of winning candidates of Indian Election 2019 is 55, and most of the data lies between 47-63 age. 

There are many ways to find Outliers in above boxplot but the accurate way is:

1. First we have to find the distance between First Quartile (Q1) and Third Quartile (Q3), which is called Interquartile (IQR)

2. Anything which is beyond Q3 + 1.5 times the IQR and anything which is less than Q1 - 1.5 times the IQR gives the possible outliers.These are those observations which are away from box.

3.Most Probable outliers are those values that are more than or less than above statement.

For Example in our above BoxPlot:-
Q1 = 47
Q3 = 63
IQR = Q3-Q1 = 16

possible outliers are 
values > = Q3 + 1.5 * IQR called capping and values < = Q1 - 1.5 * IQR calling flooring

Values > = 87 (capping)
values < = 23 (flooring)

According to this formula and after studying above histogram plot we can say that we have one outlier that is 87 and it's count is 1.

There are many ways to handle outliers.

First is we can remove that record.But it is not recommended. 

Second way is if there are so many outliers values we can assign the value nearer to that outlier. for example if values are greater than 99 percentile then we can assign the 99th percentile value, and if value is less than 1 percentile then we can assign the 1st percentile value to that outlier.

Third way is assign that value which is nearer to the median and outlier.


# 3. Describe the shape and skewness of the distribution

Ans--> In our 1st question we make histogram plot. The shape of Histogram is somehow symmetry and bell shaped. 


# 4. Based on your answer to the previous question, decide if it is appropriate to apply a transformation to your data. If no, explain why not. If yes, name the transformation applied and visualize the transformed distribution.


```{r}
summary(indian_election_df_winner$AGE)
summary(log10(indian_election_df_winner$AGE))
summary(sqrt(indian_election_df_winner$AGE))

```


```{r}
indian_election_df_winner$log_age <- log10(indian_election_df_winner$AGE)

ggplotly(indian_election_df_winner %>% 
  ggplot(aes(x = log_age)) +
  geom_histogram(color = "yellow",fill = "red",bins = 20)+
  labs(title="Distribution of Log10(Ages) for Winning Candidate", 
       y = "Count", x = "Log10(Age of Winning Candidate)") )

```


```{r}

indian_election_df_winner$sqrt_age <- sqrt(indian_election_df_winner$AGE)

ggplotly(indian_election_df_winner %>% 
  ggplot(aes(x = sqrt_age)) +
  geom_histogram(color = "yellow",fill = "red",bins = 20)+
  labs(title="Distribution of SQRT(Ages) for Winning Candidate",
       y = "Count", x = "SQRT(Age of Winning Candidate)") )

```


By comparing above three histograms one from 1st question and other two are from Log10 and SQRT, we can say that there is no need of transformation of our original data as the distribution is symmetry and bell shaped in our original histogram. 




# 5. Choose and calculate an appropriate measure of central tendency.
Ans--> The word "central tendancy" is fairly common in statistics. It's a technique to explain how your data are distributed. While central tendancy does not provide you with the fine details of your data, it does provide you with a general notion of how your data are distributed.

The mean, median, and mode are the three most widely used parameters of central tendency. The median of an ordered dataset is the value in the centre, whereas the mean or average is equal to the sum of all the values in the data set divided by the number of values in the data set. On the other side, mode shows you the dataset's most repeatable value.
So in our case we are using mean as central tendency. 

```{r}
mean(indian_election_df_winner$AGE)

```

# 6. Explain why you chose this as your measure of central tendency. Provide supporting evidence for your choice.

Because age is an issue and we need to know the average age of the candidates who would win the 2019 Indian Election, we have chosen "Mean" as the central tendency. The victorious candidates' average age is now 54.44.
Since the mean and median values in this situation are about equal, we can also compute the median here. We are using visualisation to demonstrate this proof (Box plot and Histogram).


```{r}

ggplotly(indian_election_df_winner %>% 
  ggplot(aes(y = AGE)) +
  geom_boxplot(color = "Red", fill = "cyan")+
  labs(title="Distribution of Ages for Winning Candidate", 
       x = "Count", y = "Age of Winning Candidate"))

```


In above boxplot it is clearly shown that median of age is 55.

```{r}

ggplotly(indian_election_df_winner %>% 
  ggplot(aes(x = AGE)) +
  geom_histogram(binwidth = 3,color = "yellow",fill = "red")+
  labs(title="Distribution of Ages for Winning Candidate", 
       y = "Count", x = "Age of Winning Candidate") )

```

In above Histogram we can say that mean is just near about 54.50. 


# 7.  Choose and calculate a measure of spread that is appropriate for your chosen measure of central tendency. Explain why you chose this as your measure of spread.

We have following factors for measure of spread or measure of dispersion
1. Range
2. Inter-Quartile Range 
3. Variance
4. Mean Deviation 
5. Standard Deviation

```{r}
sd(indian_election_df_winner$AGE)

```

<html><p>In above question we use Standard Deviation because When data is distributed relatively normally, the standard deviation performs exceptionally well and provides information similar to that of the IQR. But the IQR is typically favored for data that is obviously non-normal.But in our case Age is just normally distributed.</p><br> 





<P><h5><ul>Categorical Variable : <b>CATEGORY</b></ul><br>

For each categorical variable :

# 1. Create an appropriate plot to visualize the distribution of counts for this variable. 


```{r}

ggplotly(indian_election_df_winner %>% 
  ggplot(aes(x = CATEGORY)) +
  geom_bar(color = "black",fill = "cyan")+
  labs(title="Count of Different Categories of Winning Candidate", 
       y = "Count", x = "Category") )


```


# 2. Create an appropriate plot to visualize the distribution of proportions for this variable.

```{r}
pie_data <- table(indian_election_df_winner$CATEGORY)



lbls <- paste(names(pie_data), "\n", pie_data, sep="")

pie3D(pie_data, labels = lbls, 
      main = "Proportions of Different Categories of Winning Candidate")



```




# 3. Discuss any unusual observations for this variable?

Ans--> There is only one unusual observation in above categorical variable. Out of 539, 55 are from ST category or we can say that aprox only 10 % of candidates are from ST category which is like an outlier of our data.

# 4. Discuss if there are too few/too many unique values?

Ans-> There are only 3 unique values in our categorical variable  i.e General Category, SC Category and ST Category.<br>

```{r}
unique(indian_election_df_winner$CATEGORY)

```




<br><P><h5><ul><u>Bivariate Analysis</u></ul><br>

<P><h5><ul>One pair of Numeric Variable : <b>AGE</b> and <b>General Votes</b></ul><br>

<P><h5><ul>One pair of Numeric  and Categorical Variable : <b>AGE</b> and <b>Category</b></ul><br>



# 1. Create an appropriate plot to visualize the relationship between the two variables.


1. For 1st Pair

```{r}
indian_election_df_winner <- indian_election_df_winner %>% mutate(GENERAL.VOTES=GENERAL.VOTES/10000)

```


```{r}


ggplotly(indian_election_df_winner_sort %>% 
        ggplot(aes(x = AGE, y = GENERAL.VOTES)) +
        geom_point() +
        geom_smooth(formula = y ~ x, method = "lm") +
        labs(title="Comaprison of Age and General Votes",
        y = "No. of General Votes", x = " Age"))

```

2. For 2nd Pair

```{r}

ggplotly(indian_election_df_winner %>% 
  ggplot(aes(x = CATEGORY, y = AGE, fill = CATEGORY)) +
  geom_point()+
    
  labs(title="Comaprison of Category and Age of Winning Candidates ", 
       y = "Age", x = "Category"))


```


# 2. Describe the form, direction, and strength of the observed relationship. Include both qualitative and quantitative measures, as appropriate.

Ans--> When examining a scatterplot and Boxplot , we have to be able to explain the relationship between the variables that we observe.

The form, direction, and Strength of the connection, as well as the existence of any outliers, should always be included in a brief description of the association in a scatterplot.

Form: Is the relationship of either linear or nonlinear. Here in our 1st case it is slighly showing negative linear relation as Age is increasing no. of votes are  decreasing. 


Strength: Does it seem as though there is a strong, fairly strong, or weak association. In our case there is weak relationship. 

```{r}
cor(indian_election_df_winner$AGE,indian_election_df_winner$GENERAL.VOTES)


```



Direction: It tells whether the relationship is positive or negative. In our case relationship is negative and weak.




# 3. Explain what this relationship means in the context of the data?

Ans--> The significance of the correlation coefficient for the variables indicates the direction of the relationship between the two. Positive relationships are denoted with a "plus" symbol, whereas bad relationships are denoted by a "minus" sign.

Positive --> When two variables are positively correlated, they both tend to move in the same direction: If one grows, the other usually follows suit. One tends to diminish when the other does as well.

Negative --> When two variables are negatively correlated, they often move in the opposite directions: if one grows, the other tends to drop, and vice versa.



The form is refered to the whether relationship is linear or non linear.

Linear-->A straight connection is referred to as being linear since it resembles a straight line.

Curvilinear--> Because a curved connection resembles a curved line, it is referred to as being curvilinear.



We exclusively work with correlation coefficients that measure linear relationships in this Value. Other correlation coefficients exist that quantify curved relationships, but they are advanced in nature.

Perfect Relationship-->The coefficient of correlation is either +1.00 or -1.00 when two variables are linearly connected. Either favourably or negatively, it is claimed that they are precisely linearly connected.

No Relationship-->Relationship: When there is absolutely no connection between two variables, their correlation coefficient is 0.00.



For all these things we use coefficient of correlation. Predictions may be made with the use of correlations. We may expect that two variables will continue to correlate in the ahead if they have been shown to do so in the past. To forecast the value that the other variable will have in the future, we may utilise the value of one variable.




# 4. Describe the variability that you observe in the plot and how that corresponds to the strength you calculated in no. 2 above.


<html><p>Variance--> The statistical assessment of the variation in numbers within a data collection is known as variance. In more detail, variance assesses how far apart each number in the collection is from the mean (average) and, consequently, from each other.
The square root of the variance is the Standard Deviation. 

We can learn more about our data than what is often shown by conventional statistical summaries by using a scatterplot to visualise it. Bivariate data can be summarised using one of two fundamental methods: regression analysis or correlation analysis. Regression analysis describes how to leverage the relationship between the two components to forecast or control one variable using the other. The standard error of estimate and coefficient of determination, both equal to the square of the correlation r, are two indicators of how well a regression analysis performed. The former indicates the typical size of prediction errors, while the latter indicates the proportion of the Y variable's variability that is "explained" by the X variable.

Now, in our first scatter plot, we can observe that the majority of the data is present for both the variable x and y axis in the middle of the graph.

According to strength of our data our scatter plot is weak in relationship. I must say it is negative in relationship.<br>





<br><P><h3><ul><b>Tulaib Bin Ayyub (0789141)</b></ul><br>
<P><h5><ul><u>Univariate Analysis</u></ul><br>

<P><h5><ul>Numeric Variable : <b>Postal Votes</b></ul><br>



```{r}
df_ind_elec <- read.csv("Indian_Election_2019.csv")
df_ind_elec
```
#Univariate 
#Numeric variable:

# Ques1. Create an appropriate plot to visualize the distribution of this variable.

```{r}

ggplotly(df_ind_elec %>% 
  ggplot(aes(POSTAL.VOTES))+
  geom_histogram(binwidth = 70, color = "darkblue")+
    labs(title = "DISTRIBUTION OF POSTAL VOTES", x = "Number Of Postal Votes", y = "Count"))

```


# Ques2. Consider any outliers present in the data. If present, specify the criteria used to identify them and provide a logical explanation for how you handled them.

```{r}
ggplotly(df_ind_elec %>% 
           ggplot(aes(y = POSTAL.VOTES))+
           geom_boxplot(fill = "skyblue"))
```

Ans2. After looking at the generated boxplot, we can clearly see that there are multiple outliers. To handle the outliers we can impute them with median if they are close to median or we can impute them with any value closer to the outliers which is not an outlier.


# Ques3. Describe the shape and skewness of the distribution.

```{r}
mean(df_ind_elec$POSTAL.VOTES)
```
Ans3. After finding the mean above and median in question 2, we can say that the shape and skewness of the distribution are unimodel and right skewed because most of the data are in left part.


# Ques4. Based on your answer to the previous question, decide if it is appropriate to apply a transformation to your data. If no, explain why not. If yes, name the transformation applied and visualize the transformed distribution.




```{r}
df_ind_elec <- df_ind_elec %>%
  mutate(sqrt_pst.vote = sqrt(POSTAL.VOTES))

ggplotly(df_ind_elec %>% 
  ggplot(aes(sqrt_pst.vote))+
  geom_histogram(binwidth = 10, fill = "skyblue", color = "black")+
    labs(title = "DISTRIBUTION USING SQUARE ROOT TRANSFORMATION", x = "sqrt(POSTAL VOTES)", y = "Count"))
```

Ans4. After using Log10 Transformation it is difficult to interpret the visualization because the data has too many zero values which gives us negative infinity.
And after using square root transformation it is easy to interpret the distribution which is in a shape of unimodel and the distribution is right skewed.


# Ques5. Choose and calculate an appropriate measure of central tendency.
```{r}
mean(df_ind_elec$POSTAL.VOTES)
```

# Ques6. Explain why you chose this as your measure of central tendency. Provide supporting evidence for your choice.

```{r}
ggplotly(df_ind_elec %>% ggplot(aes(y = POSTAL.VOTES))+
  geom_boxplot(fill = "skyblue"))
```

 Ans6. Chose this because it is showing the average of postal votes which is very different in comparison to the median. In this boxplot we can see the median is low i.e., 316.00 and the mean was 990.7106 as we saw in previous answer. 


# Ques7. Choose and calculate a measure of spread that is appropriate for your chosen measure of central tendency. Explain why you chose this as your measure of spread.
```{r}
sd(df_ind_elec$POSTAL.VOTES)
```

Ans. To calculate measures of spread we can use minimum value, maximum value, standard deviation, variance, interquartile(IQR), etc. We are taking standard deviation and the value is high so the value in the data set are spread over a wide range.


<P><h5><ul>Categorical Variable : <b>State</b></ul><br>


# Categorical variable:

# Ques1. Create an appropriate plot to visualize the distribution of counts for this variable.

```{r}
ggplotly(df_ind_elec %>% ggplot(aes(STATE))+
  geom_bar(fill = "skyblue", color = "black")+
    coord_flip()+
    labs(title = "DISTRIBUTION OF STATES", x = "States", y = "Count"))
```


# Ques2. Create an appropriate plot to visualize the distribution of proportions for this variable.

```{r}
df_ind_elec %>% 
  ggplot(aes(x = factor(1), fill = factor(STATE)))+
  geom_bar(width = 1)+
  coord_polar(theta = 'y', start = 0)+
  labs(title = "PROPORTIONS OF DIFFERENT STATES", x = "States")


```



# Ques3. Discuss any unusual observations for this variable?

Ans3. Having too many value in this variable which is making it hard to interpret the visualization.


# Ques4. Discuss if there are too few/too many unique values?

```{r}
unique(df_ind_elec$STATE)
```
Ans4. Yes there are too many unique values i.e., 36. 



<br><P><h5><ul><u>Bivariate Analysis</u></ul><br>

<P><h5><ul>One pair of Numeric Variable : <b>AGE</b> and <b>Postal Votes</b></ul><br>

<P><h5><ul>One pair of Numeric  and Categorical Variable : <b>AGE</b> and <b>Winner</b></ul><br>



# Ques1. Create an appropriate plot to visualize the relationship between the two variables.

Ans1. 
1. Plot using two numerical variables.
```{r}
df_ind_elec <- df_ind_elec %>% 
                mutate(POSTAL.VOTES = POSTAL.VOTES/100)
```


```{r}
ggplotly(df_ind_elec %>% 
           ggplot(aes(x = AGE, y = POSTAL.VOTES))+
           geom_point(color = "skyblue")+
           geom_smooth(method = "gam", 
                       formula = y ~ s(x, bs = "cs")))
```

 2. Plot using one numerical and one categorical variable.
```{r}
ggplotly(df_ind_elec %>%
  ggplot(aes(x = WINNER, y = AGE))+
  geom_point(color = "skyblue"))
```

# Ques2. Describe the form, direction, and strength of the observed relationship. Include both qualitative and quantitative measures, as appropriate.

```{r}
cor( df_ind_elec$AGE, df_ind_elec$POSTAL.VOTES, 
     use = "complete.obs")
```

Ans2. Form tells if the relationship is linear or non-linear and in our case the form is showing linear correlation.
Direction tells if the correlation is positive or negative and in our case it is showing positive correlation.
Strength tells weather the correlation is weak strong or fairly strong  and in our case the relation between variables is fairly strong i.e., 0.12936.


# Ques3. Explain what this relationship means in the context of the data.

Ans3. This relationship means to understand and find the correlation between two variables. So that we can find the positive, negative, curvilinear relationship. We can say the relationship is perfect if the value lies between -1 to +1 and a no relationship when no relation is found so the correlation is 0. 
To find the relationship we use correlation coefficient.


# Ques4. Describe the variability that you observe in the plot and how that corresponds to the strength
you calculated in #2 above.

Ans4. By utilizing a scatter plot to visualize our data, we may discover more about it than what is frequently shown by traditional statistical summaries. One of the two primary techniques—correlation analysis or regression analysis—can be used to summarize bivariate data. Regression analysis explains how to take advantage of the connection between the two elements to predict or regulate one parameter using the other. Two measures of how well a regression analysis worked are the standard error of estimate and coefficient of determination, both equal to the square of the correlation r. Indicated by the latter is the percentage of the Y variable's variability that can be "explained" by the X variable, the former indicating the average size of prediction mistakes.
Scatter plot shows a rather good and fairly strong relationship with the quality of our data and it is a possibly positive relationship









<br><P><h3><ul><b>Alisha Mahajan(0802631)</b></ul><br>
<P><h5><ul><u>Univariate Analysis</u></ul><br>

<P><h5><ul>Numeric Variable : <b>GENERAL VOTES</b></ul><br>



```{r} 
ind_elec <- read.csv("Indian_election_2019.csv")

```

# 1. Create an appropriate plot to visualize the distribution of this variable.

```{r}

ind_elec <- ind_elec %>%
  mutate(GENERAL.VOTES = GENERAL.VOTES/1000)
```


```{r}


ggplot(ind_elec, aes(x = GENERAL.VOTES))+
  geom_histogram( color = "BLUE", fill = "YELLOW") +
  labs(title="Distribution of general votes in 2019 election", 
       y = "Count", x = "No. of general votes") 
```

In the above histogram, it can be seen that there is right skewed distribution where general votes lies mostly on left side.

# 2.Consider any outliers present in the data. If present, specify the criteria used to identify them and provide a logical explanation for how you handled them.

```{r}
ggplotly(ind_elec %>% 
  ggplot(aes(y = GENERAL.VOTES)) +
  geom_boxplot(color = "Red", fill = "blue")+
  labs(title="Distribution of General votes in 2019 election", 
       x = "Count", y = "General Votes"))
```
In above box plot, it can be seen that there are many outliers in this plot which can be calculated as:

 Interquartile (IQR) = Q3-Q1
                     = 485.81 - 21.03
                     = 464.78

possible outliers:   values > = Q3 + 1.5 * IQR (capping) and values < = Q1 - 1.5 * IQR (flooring)
 
 values > = 1182.98 and values < = -676.14 
 
 So, according to this formula, there is no outliers in this plot. but in my analysis there are some outliers which falls between 485.81 and 1066.82.
 
 How to handel outliers: 
 
 1. first way to handle these outliers is to simply delete it or remove it. But this is not an appropriate way.
 2. second way is to assign that value which is nearer value.
 3. And Third way is to find the mean, if it is nearby the values then we take that value. 
 
 
# 3. Describe the shape and skewness of the distribution?
Ans: The shape of the distribution is unimodel as it has one hump and it can be clearly seen that there is right skewed distribution where general votes lies mostly on left side.
 
 
# 4. Based on your answer to the previous question, decide if it is appropriate to apply a transformation to your data. If no, explain why not. If yes, name the transformation applied and visualize the transformed distribution.
 
```{r}
 summary(ind_elec$GENERAL.VOTES)
```

```{r}
summary(log10(ind_elec$GENERAL.VOTES))
```
```{r}
summary(sqrt(ind_elec$GENERAL.VOTES))
```

```{r}
ind_elec$log_gvote <- log10(ind_elec$GENERAL.VOTES)
```


```{r}


ggplotly(ind_elec %>% 
  ggplot(aes(x = log_gvote)) +
  geom_histogram(color = "yellow",fill = "red",bins = 20)+
  labs(title="Distribution of Log10(GENERAL VOTES) for Candidate", 
       y = "Count", x = "Log10(General Votes of Candidate)") )
```
 
```{r}
ind_elec$sqrt_gvotes = sqrt(ind_elec$GENERAL.VOTES)
```
 
 
```{r}

ggplotly(ind_elec %>% 
  ggplot(aes(x = sqrt_gvotes)) +
  geom_histogram(color = "yellow",fill = "red",bins = 20)+
  labs(title="Distribution of SQRT(GENERAL VOTES) for Candidate", 
       y = "Count", x = "SQRT(General Votes of Candidate)") )

```
After comparing above 3 plots, 1 in question 2nd and 2 in question 4th i.e. log10 and sqrt, it can be decided that we can take Ist plot which is symmetrical rather that other two plots that are not symmetrical(forming 2 humps.)
 
# 5 . Choose and calculate an appropriate measure of central tendency. 
Ans: Central tendency: The statistical measure that designates one value as being representative of a whole distribution is known as central tendency. [2] The complete set of data will be accurately described. It is the single value that best characterizes or encapsulates the information gathered.

Mean, median and mode are three ways that are used to measure central tendency.

```{r}
median_value <- median(ind_elec$GENERAL.VOTES)
median_value

```

```{r}
mean_value <- mean(ind_elec$GENERAL.VOTES)
mean_value
```
# 6. Explain why you chose this as your measure of central tendency. Provide supporting evidence for your choice .
Ans: After analyzing central tendency for mean and median of variable general votes, I take mean as the measure for central tendency because it it more accurate than median and also our data is mostly on left side and also we are calculated average of general  votes. so, mean is best suited for this variable.


# 7. Choose and calculate a measure of spread that is appropriate for your chosen measure of central tendency. Explain why you chose this as your measure of spread.
Ans:
We can calculate measure of spread in many ways like Range, IQR, Variance, Mean deviation, Standard deviation. but here I am calculating variance for general votes:
```{r}
var(ind_elec$GENERAL.VOTES)

```
The average squared deviation from the mean, also known as variance, gives us the average dispersion from the mean for a given set of data. However, if an outlier is present, the value returned after squaring the deviation from the mean would be excessively large, which immediately leads us to the conclusion that an outlier is present in the data set. When you calculate the variance, you'll see that the result is abnormally high in the big picture. We basically take the square root of these numbers to restore them to their normal value and give us a number that is much more typical in order to account for this.


<br><P><h5><ul>Categorical Variable : <b>EDUCATION</b></ul><br>

# 1.Create an appropriate plot to visualize the distribution of counts for this variable.

```{r}
ggplotly(ind_elec %>% 
  ggplot(aes(x = EDUCATION)) +
  geom_bar(color = "bLUE",fill = "PINK")+
  labs(title="Count of Education Candidate", 
       y = "Count", x = "Education") )
```
# 2. Create an appropriate plot to visualize the distribution of proportions for this variable.

```{r}

ind_elec %>% 
  ggplot(aes(x = factor(1), fill = factor(EDUCATION)))+
  geom_bar( width = 1)+
  coord_polar(theta = 'y', start = 0)+
  labs(title="Proportions of Education of Candidate", 
       y = "Count", x = "Education") 
  


```


# 3. Discuss any unusual observations for this variable.
Ans: There are some unusual observations of Eductaion categorical variable like 

1. In some observations there are duplicate values.
2. In some of the cases there are missing values.
3. In this variable some values are "Not Available"


# 4. Discuss if there are too few/too many unique values?
Ans:There are total 13 unique values, we have in this categorical variable.

```{r}
unique(ind_elec$EDUCATION)
```


<br><P><h5><ul><u>Bivariate Analysis</u></ul><br>

<P><h5><ul>One pair of Numeric Variable : <b>AGE</b> and <b>Total Votes</b></ul><br>

<P><h5><ul>One pair of Numeric  and Categorical Variable : <b>AGE</b> and <b>STATE</b></ul><br>

# 1. Create an appropriate plot to visualize the relationship between the two variables.

```{r}

ind_elc <- ind_elec %>% 
            mutate(TOTAL.VOTES=TOTAL.VOTES/1000)


```

```{r}
ggplotly(ind_elc%>% 
        ggplot(aes(x = AGE, y = TOTAL.VOTES, color = CATEGORY)) +
        geom_point() +
        geom_smooth(formula = y ~ x, method = "lm") +
        labs(title="Comparison of Age and Total Votes",
        y = "No. of Total Votes", x = " Age"))

```


2. For 2nd pair 

```{r}

ggplotly(ind_elc %>% 
  ggplot(aes(x = AGE, y = STATE, fill = STATE)) +
  geom_point()+
    
  labs(title="Comparison of State and Age of Candidates ", 
       y = "State", x = "Age"))


```
# 2. Describe the form, direction, and strength of the observed relationship. Include both qualitative
and quantitative measures, as appropriate. 

Ans--> In a scatterplot, a quick summary of the link should always include the form, direction, and strength of the connection as well as the presence of any outliers.

Form: Is the relationship of either linear or nonlinear. Here in our 1st case it is slighly showing positive linear relation as Age is increasing no. of Total votes are  Increasing.

Strength : It tells us how strong is relation between the variables, either weak, strong or fairly strong. But in this case Our relation is fairly strong and positive. Here below we are calculating correlation coefficient within two variables.


```{r}

cor(ind_elc$AGE, ind_elc$TOTAL.VOTES, use = "complete.obs")

```
Direction: It tells whether the relationship is positive or negative. In our case relationship is Positive and fairly strong.

# 3 Explain what this relationship means in the context of the data.

Ans--> Understanding and determining the correlation between two variables is what this connection refers to. in order to identify the curvilinear, positive, and negative relationships. If the value is between -1 and +1, then the relationship is perfect; otherwise, there is no association, and the correlation is 0.
We utilize the correlation coefficient to discover the relationship.
In our case correlation coefficient is positive i.e + 0.208

# 4 Describe the variability that you observe in the plot and how that corresponds to the strength
you calculated in #2 above.

Ans--> The Variance is the numerical measure of how thew data is spread across the mean. The R language's var() function calculates a vector's sample variance. It serves as a gauge for how much a value deviates from the mean. The square root of the variance is the standard deviation. 

Two measures of how well a regression analysis worked are the standard error of estimate and coefficient of determination, both equal to the square of the correlation r. Indicated by the latter is the percentage of the Y variable's variability that can be "explained" by the X variable, the former indicating the average size of prediction mistakes.

Now in our first Scatter plot most of the data is present in the bottom of the graph, which means mostly values of total votes are less.


According to strength of our data our scatter plot is fairly strong in relationship. I must say it is positive relation.

